Trying to understand the point of vdroop +90% in the bios.

My setup
9900K
EVGA Z390 FTW
Corsair LPX 3200

My goal is to under volt my CPU at stock speeds or maybe 4.8ghz all core if thermals support it.
In testing I left the vcore at auto to see the differences in all the +vdroop settings.
Doing this (vcore set to auto) with the +90% vdroop setting kind of achieved similar vcore results to setting the vcore to 1.17 adaptive with -50% vdroop.
Cinebech r20 and time spy for testing. HWmonitor and eleet for vcore and temp monitoring.
What are the benefits/drawbacks of leaving the vcore at auto with a +90% large vdroop vs setting a low adaptive vcore (1.17 as an edample) with -50% less vdroop?

Separate question. Any reason why time spy shows a higher CPU score when all cores are locked at 4.8ghz compared to say cores 0-3 at 4.9 and cores 4-7 to 4.8ghz? No AVX offset or any other bios changes that I’m aware of. Shouldn’t the CPU time spy scores be the same?

Thanks

Give this a look - for great in depth information     https://xdevs.com/guide/e399ocg/
 

darli328

Cool GTX
Give this a look - for great in depth information     https://xdevs.com/guide/e399ocg/
 

Thank you! Really good information.
Since I have the FTW board I know there’s less features compared to the dark.
Question on adaptive voltage if I’m reading it correctly.
I set my adaptive voltage below 1.2 with 0 offset and as I mention it would still go up to 1.23.
The link reads as if adaptive and auto are basically the same thing and it will send whatever voltage it thinks it needs based off the core clock. To account for this I’m guessing I need to set a negative offset in adaptive voltage since the target voltage is really just a window that it can go above and below?
Is that correct based on my goals to under volt my CPU.
Thanks

 
offhand I do not know the answer to your question & do not own that MB
 
many be someone else in the Community can help with that