feathers632 I know very well that the only really effective way to cool a peltier (especially above a certain power) is using water.
feathers632 The water chiller is made by sandwiching 6 or 8 peltiers between 2 hard disk waterblocks. One waterblock is connected to the cold side of the peltiers and the other block cools the hot side. The hot side hard disk waterblock will be cooled by my extreme water loop. The cold side peltier hard disk block will feed peltier chilled coolant to the CPU waterblock. In other words, the hot side water loop is a full water loop whereas the cold side loop has no radiator, just the peltier chilling and a pump feeding cpu waterblock. The peltiers will be 6 - 8 100w all fed with low voltage (perhaps 3 - 4 volts). ?????
For a 226W Qmax module at 12v: V = 12vdc I = 24 * (12/15.2) = 18.95A P = 12 * 18.95 = 227.4W Q = 226 * (12/15.2)^2 = 140.86W DT = 69 * (12/15.2)^2 = 43K L = 227.4-140.86 = 86.51W
lehpron ** This post contains a lot of math, prepare yourself ** Editted for proper math symbols
humbleBe 1. What happens if you connect two peltiers directly together with both their cold sides facing each other? - Please assume that the current supplied and the heat dispersal is optimal and exactly the same for both and that the pelts are insulated against condensation.
humbleBe 2. If you then put a copper water block between the two peltiers how thick would it need to be to achieve optimal cooling efficiency?i.e. Is the water block cooled more or do the pelts work against each other.
humbleBe How far apart they should be - seems 1" is good.
humbleBe One more general question: If you are feeding -10 celcius fluid to a modern intel CPU (eg: stock i7-2600k under load) at a typical 1 GPM what is the temperature of the water exiting the block? - is it still near ambient or is it much hotter requiring a radiator before going back to the pelt for cooling?